Direct Variation Word Problems Worksheet

By | July 30, 2025

Are you ready to tackle direct variation word problems? Direct variation, also known as direct proportion, is a fundamental concept in mathematics that describes a relationship where two variables change at a constant rate. Understanding and applying this concept is crucial for solving various real-world problems. That’s where a well-designed “Direct Variation Word Problems Worksheet” comes in handy! It’s the perfect tool to solidify your grasp on the subject and boost your problem-solving skills.

This worksheet provides a series of carefully crafted word problems that challenge you to identify direct variation relationships, set up proportions, and solve for unknown values. It’s not just about plugging numbers into formulas; it’s about understanding the underlying logic and applying it effectively. By working through these problems, you’ll develop a deeper understanding of how direct variation manifests in everyday scenarios, from calculating the cost of multiple items to determining the distance traveled based on speed and time.

The worksheet typically starts with simpler problems to build your confidence and gradually progresses to more complex scenarios, allowing you to steadily improve your problem-solving abilities. You’ll encounter problems involving distance, rate, time, cost, weight, and more, all presented within the framework of direct variation. Each problem is designed to encourage critical thinking and analytical reasoning, helping you develop a systematic approach to problem-solving.

Using a Direct Variation Word Problems Worksheet offers several benefits. First, it provides ample practice to master the concept. Second, it helps you identify areas where you might be struggling, allowing you to focus your efforts on those specific areas. Third, it promotes independent learning and self-assessment. By working through the problems and checking your answers (usually provided separately), you can track your progress and identify areas for improvement.

Whether you’re a student learning about direct variation for the first time or someone looking to refresh your skills, a well-structured worksheet is an invaluable resource. It’s an engaging and effective way to learn, practice, and master the art of solving direct variation word problems.

Direct Variation Word Problems: Sample Problems and Solutions

Let’s imagine your Direct Variation Word Problems Worksheet includes these examples (the actual content of a worksheet will vary!):

Example Problems:

  1. The cost of gasoline varies directly with the number of gallons purchased. If 10 gallons of gasoline cost $35, what is the cost of 25 gallons of gasoline?
  2. Hooke’s Law states that the distance a spring stretches varies directly with the weight attached to the spring. If a 5 kg weight stretches a spring 8 cm, how much will a 2 kg weight stretch the same spring?
  3. The number of apples purchased is directly proportional to the total cost. If 12 apples cost $6, what will 20 apples cost?
  4. The distance a car travels varies directly with the time spent traveling. If a car travels 240 miles in 4 hours, how far will it travel in 7 hours?

Solutions:

Below is a representation of how the answers to the example problems might be presented. Remember, the specific format of the answers will vary depending on the worksheet.

  1. Problem 1:

    Let ‘c’ be the cost and ‘g’ be the number of gallons.

    c = kg, where k is the constant of variation.

    35 = k * 10 => k = 3.5

    So, c = 3.5g

    For 25 gallons: c = 3.5 * 25 = $87.50

  2. Problem 2:

    Let ‘d’ be the distance the spring stretches and ‘w’ be the weight.

    d = kw, where k is the constant of variation.

    8 = k * 5 => k = 1.6

    So, d = 1.6w

    For a 2 kg weight: d = 1.6 * 2 = 3.2 cm

  3. Problem 3:

    Let ‘C’ be the total cost and ‘a’ be the number of apples.

    C = ka, where k is the constant of variation.

    6 = k * 12 => k = 0.5

    So, C = 0.5a

    For 20 apples: C = 0.5 * 20 = $10

  4. Problem 4:

    Let ‘d’ be the distance and ‘t’ be the time.

    d = kt, where k is the constant of variation.

    240 = k * 4 => k = 60

    So, d = 60t

    For 7 hours: d = 60 * 7 = 420 miles

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